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(A) Just after the switch $S$ is closed, the current through the inductors cannot change instantaneously. Since the current was zero before closing th

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$2.25$

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(A) Just after the switch $S$ is closed, the current through the inductors cannot change instantaneously. Since the current was zero before closing the switch, it remains zero immediately after closing the switch.Therefore, the branches containing inductors act as open circuits (infinite resistance).The circuit simplifies to a series combination of the battery and two resistors of resistance $R$ each.The equivalent resistance of the circuit is $R_{eq} = R + R = 2.0 \, \Omega + 2.0 \, \Omega = 4.0 \, \Omega$.The current $i$ in the circuit is given by Ohm's law:$i = \frac{E}{R_{eq}} = \frac{9 \, V}{4.0 \, \Omega} = 2.25 \, A$.

The figure shows a circuit that contains three resistors with resistance $R = 2.0 \, \Omega$, two inductors with inductance $L = 2.0 \, mH$, and an ideal battery with $emf$ $E = 9 \, V$. The current $i$ just after the switch $S$ is closed will be .... $A$.

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